Odpowiedź:
[tex]9 \frac{3}{4} \div 2 \frac{6}{10} - \frac{3}{4} \times 3 \frac{2}{10} = \frac{39}{4} \times \frac{1}{2} \times \frac{6}{10} - \frac{3}{4} \times 3 \times \frac{1}{5} = \frac{39}{4} \times \frac{3}{10} - \frac{9}{20} = \frac{99}{40} = 2 \frac{19}{40} [/tex]
