[tex]dane:\\m = 2 \ kg\\E_{k} = 36 \ J = 36 \ \frac{kg\cdot m^{2}}{s^{2}}\\szukane:\\v = ?\\\\Rozwiazanie\\\\E_{k} = \frac{mv^{2}}{2} \ \ /\cdot\frac{2}{m}\\\\v^{2} = \frac{2E_{k}}{m}\\\\v = \sqrt{\frac{2E_{k}}{m}}[/tex]
[tex]v = \sqrt{\frac{2\cdot36\frac{kg\cdot m^{2}}{s^{2}}}{2kg}}} = \sqrt{36\frac{m^{2}}{s^{2}}}= 6\frac{m}{s}\\\\Odp. \ C.[/tex]
