Odpowiedź:
zad5
a)[tex]\sqrt{2} *\sqrt{8} =\sqrt{2*8} =\sqrt{16} =4[/tex]
b)[tex]\sqrt{12} *\sqrt{3} =\sqrt{12*3} =\sqrt{36} =6[/tex]
c)[tex]\sqrt[3]{4} *\sqrt[3]{2} =\sqrt[3]{4*2} =\sqrt[3]{8}=2[/tex]
d)[tex]\sqrt[3]{8} *\sqrt[3]{64} =2*4=8[/tex]
e)[tex]\sqrt{25*16} =5*4=20[/tex]
f)[tex]\sqrt{144*81} =12*9=108[/tex]
g)[tex]\sqrt[3]{16} *\sqrt[3]{4} =\sqrt[3]{16*4}=\sqrt[3]{64} =4[/tex]
h)[tex]\sqrt[3]{27*125} =3*5=15[/tex]
zad6
a)[tex]\sqrt{8} :\sqrt{2} =\sqrt{8:2} =\sqrt{4}=2[/tex]
b)[tex]\sqrt{45} :\sqrt{5} =\sqrt{45:5} =\sqrt{9} =3[/tex]
c)[tex]\sqrt{\frac{1}{4}:\frac{1}{9} } =\sqrt{\frac{1}{4} *\frac{9}{1} } =\frac{3}{2} =1\frac{1}{2}[/tex]
d)[tex]\sqrt{\frac{5}{9} } :\sqrt{5} =\sqrt{\frac{5}{9} *\frac{1}{5} } =\sqrt{\frac{1}{9} } =\frac{1}{3}[/tex]
e)[tex]\sqrt[3]{108} :\sqrt[3]{4} =\sqrt[3]{108:4} =\sqrt[3]{27} =3[/tex]
f)[tex]\sqrt[3]{\frac{4}{3} } :\sqrt[3]{\frac{9}{2} } =\sqrt[3]{\frac{4}{3}*\frac{2}{9} } =\sqrt[3]{\frac{8}{27} } =\frac{2}{3}[/tex]
g)[tex]\sqrt[3]{81:3} =\sqrt[3]{27} =3[/tex]
h)[tex]\sqrt[3]{216:125} =6:5=\frac{6}{5} =1\frac{1}{5}[/tex]
Szczegółowe wyjaśnienie:
