Zad.1
[tex]heksen - C_6H_{12}[/tex]
[tex]m_C = 12u\\m_H = 1u\\m_{C_6H_{12}}=6*12u+12*1u=72u+12u=84u[/tex]
Odp. 84u.
Zad.2
[tex]m_C = 12u\\m_H = 1u\\m_{C_3H_{8}}=3*12u+8*1u=36u+8u=44u[/tex]
100% ➡ 44u
x% ➡ 3*12u
100% ➡ 44u
x% ➡ 36u
[tex]x=\frac{36*100}{44}=\frac{900}{11}=81\frac{9}{11}[/tex]
Odp. [tex]81\frac{9}{11}[/tex] %.
Zad.3
Wzór: [tex]C_5H_{10}[/tex]
Nazwa alkenu: [tex]penten[/tex]
Wzór strukturalny:
H H H
| | |
H - C = C - C - C - C - H
| | | | |
H H H H H
Wzór półstrukturalny:
[tex]CH_2=CH-CH_2-CH_2-CH_3[/tex]
Zad.4
[tex]2C_4H_{10}+13O_2~~->~~8CO_2+10H_2O[/tex]
Zad.5
[tex]C_5H_{12}+Cl_2~~->~~C_5H{11}Cl + HCl[/tex]
[tex]C_7H_{14}+Br_2~~->~~C_7H_{13}Br+HBr[/tex]
[tex]C_3H_6+HF~~->~~C_3H_7F[/tex]
Zad.5
[tex]C_2H_4+3O_2~~->~~2CO+2H_2O[/tex]
[tex]m_C=12u\\m_H=1u\\m_{C_2H_4}=2*12u+4*1u=24u+4u=28u[/tex]
[tex]m_H=1u\\m_O=16u\\m_{2H_2O}=2*(2*1u+16u)=2*18u=36u[/tex]
28u ➡ 36u
100g ➡ x g
[tex]x= \frac{100*36}{28}=\frac{100*9}{7}=\frac{900}{7}=128\frac47[/tex]
Odp.[tex]128\frac47[/tex] g.
