Odpowiedź:
y=a(x-p)²+q
p=-b/2a
q=-Δ/4a
a)
f(x)=3x²-12x-2
p=-b/2a=12/6=2
q=-Δ/4a=-120/12=-10
y=3(x-2)²-10
b)
f(x)=-x²+2x
p=-2/2=-1
q=-4/4=-1
y=-(x-1)²-1
c)
f(x)=-4x²-1
p=0
q=-1
y=-4(x-0)²-1
d)
f(x)=-1/2x²-2x+6
p=1/2*-4=-2
q=8
y=-1/2(x+2)²+8
f(x)=1/4(x-8)²-20
y=1/4(x²-16x+64)-20
y=1/4x²-4x+44
f(x)=-(x+5)²+2
f(x)=-(x²+10x+25)+2
f(x)=-x²-10-23
Szczegółowe wyjaśnienie:
