Odpowiedź:
[tex]\begin{cases}\frac{x-1}{2}+\frac{y-1}{3}=1\ \ /*6\\\frac{x-2}{8}-\frac{y-1}{4}=2\ \ /*8\end{cases}\\\\\\\begin{cases}3(x-1)+2(y-1)=6\\x-2-2(y-1)=16\end{cases}\\\\\\\begin{cases}3x-3+2y-2=6\\x-2-2y+2=16\end{cases}\\\\\\\begin{cases}3x+2y=6+3+2\\x-2y=16\end{cases}\\\\\\\begin{cases}3x+2y=11\\x=16+2y\end{cases}\\\\\\3(16+2y)+2y=11\\\\48+6y+2y=11\\\\8y=11-48\\\\8y=-37\ \ /:8\\\\y=-\frac{37}{8}\\\\y=-4\frac{5}{8}[/tex]
[tex]x=16+\not2^1*(-\frac{37}{\not8_{4}})=16-\frac{37}{4}=15\frac{4}{4}-9\frac{1}{4}=6\frac{3}{4}\\\\\\\begin{cases}x=6\frac{3}{4}\\y=-4\frac{5}{8}\end{cases}[/tex]
