[tex]a)\\\\x+ 2\frac{1}{2}=\frac{4x+3}{4} -\frac{2-3x}{8}\\\\x+ \frac{5}{2}=\frac{4x+3}{4} -\frac{2-3x}{8} \ |*8\\\\8x+20=2(4x+3)-(2-3x)\\\\8x+20=8x +6- 2+3x \\\\8x-8x-3x= 6- 2 -20\\\\-3x=-16\ \ |:(-3)\\\\x=\frac{16}{3}=5\frac{1}{3}[/tex]
[tex]b)\\\\ (2x-5)(3x+3)=(x-2)(6x+7)-9\\\\6x^2+6x-15x-15 =6x^2+7x-12x-14-9\\\\6x^2-9x-15 =6x^2-5x-23\\\\6x^2-9x-6x^2+5x=-23+15\\\\-4x= -8\ \ |:(-4)\\\\x=2[/tex]
