Odpowiedź:
[tex](x-8)^{2} = x^{2} - 16x+64\\\\(6-x)^{2} = x^{2} -12x+36\\\\(2x-7)^{2} = 4x^{2} - 28x+49\\\\(\sqrt{2} - x) ^{2} = 2-2\sqrt{2} + x^{2} \\\\(\sqrt{5} - \sqrt{11} ) ^{2} = 5-2\sqrt{55} + 11 = 16-2\sqrt{55}[/tex]
Wzór jaki użyłam:
[tex](a-b)^{2} = a^{2} - 2ab + b^{2}[/tex]
