zadanie 1
M CO2 = 12g/mol + 2*16g/mol = 44g/mol
M H2SO4 = 2*1g/mol + 32g/mol + 4*16g/mol = 98g/mol
M Na2O = 2*23g/mol + 16g/mol = 62g/mol
M Ca(OH)2 = 40g/mol + 2*16g/mol + 2*1g/mol = 74g/mol
M HNO3 = 1g/mol + 14g/mol + 3*16g/mol = 63g/mol
M Fe2O3 = 2*56g/mol + 3*16g/mol = 160g/mol
M Al2(SO4)3 = 2*27g/mol + 3*32g/mol + 4*3*16g/mol = 342g/mol
zadanie 2
a) M Na2SO4 = 2*23g/mol + 32g/mol + 4*16g/mol = 142g/mol
1 mol - 142g
5 moli - x
x = 5moli * 142g / 1mol = 710g
b) M Cl2 = 2*35,5g/mol = 71g/mol
1 mol - 71g
2,5 mola - x
x = 2,5mola * 71g / 1mol =177,5g
c) M H2S = 2*1g/mol + 32g/mol = 34g/mol
1 mol - 34g
8 moli - x
x = 8moli*34g/1mol = 272g
zadanie 3
1. CO2
M CO2 = 12g/mol + 2*16g/mol = 44g/mol
%C = 12g/44g * 100% = 27,27%
%O = 2*16g/44g * 100% = 72,73%
2. HNO3
M HNO3 = 1g/mol + 14g/mol + 3*16g/mol = 63g/mol
%H = 1g/63g * 100% = 1,59%
%N = 14g/63g * 100% = 22,22%
%O = 3*16g/63g * 100% = 76,19%
3. Al(OH)3
M Al(OH)3 = 27g/mol + 3*16g/mol + 3*1g/mol = 78g/mol
%Al = 27g/78g * 100% = 34,62%
%O = 3*16g/78g * 100% = 61,54%
%H = 3*1g/78g * 100% = 3,85%
4. Na3PO4
M Na3PO4 = 3*23g/mol + 31g/mol + 4*16g/mol = 164g/mol
%Na = 3*23g/164g * 100% = 42,07%
%P = 31g/164g * 100% = 18,90%
%O = 4*16g/164g * 100% = 39,02%
zadanie 4
a) 1 mol - 6,02 * 10^23 atomów
x moli - 14,07 * 10*23 atomów
x = 2,34 mola
b) 1 mol - 6,02 * 10^23 cząsteczek
x moli - 8,02 * 10^23 cząsteczek
x = 1,33 mola
c) 1 mol - 6,02 * 10^23 cząsteczek
x moli - 20,05 * 10^23 cząsteczek
x = 3,33 mola
