[tex]Zadanie\\\\c)\\\\3x(x-5)=(x-2)(3x-3)\ ;\ \ \ x=-1\\\\3\cdot(-1)(-1-5)=(-1-2)[3\cdot(-1)-3]\\\\ -3\cdot(-6)=-3(-3-3)\\\\18=-3\cdot(-6)\\\\18=18\\\\L=P\\\\Liczba\ (-1)\ spelnia\ to\ rownanie\\\\d)\\\\\frac{3}{5}x-(\frac{7}{9}x-\frac{1}{4})=\frac{2-(x+3)}{4}\ ;\ \ \ x=0\\\\ \frac{3}{5}\cdot0-(\frac{7}{9}\cdot0-\frac{1}{4})=\frac{2-(0+3)}{4}\\\\0-(0-\frac{1}{4})=\frac{2-3}{4}\\\\\frac{1}{4}\ne-\frac{1}{4}\\\\L\ne P\\\\ Liczba\ 0\ nie\ spelnia\ tego\ rownania[/tex]
