Odpowiedź:
a)
T = 12(v - 1/3x) = 12v - 4x
4x = 12v - T
x = (12v - T)/4
b)
V + a = 6(a + bx)
V + a = 6a + 6bx
6bx = V + a - 6a = V - 5a
x = (V - 5a)/6b
[tex]Zadanie\\\\a)\\\\T=12(v-\frac{1}{3}x)\\\\T=12v-4x\ \ \ \mid-12v\\\\T-12v=-4x\ \ \ \mid:(-4) \\\\\frac{12v-T}{4}=x\\\\x=\frac{12v-T}{4}\\\\b)\\\\V+a=6(a+bx)\\\\V+a=6a+6bx\ \ \ \mid-6a\\\\V-5a=6bx\ \ \ \mid:6b\\\\\frac{V-5a}{6b}=x\\\\ x=\frac{V-5a}{6b}\\\\Zal.\ b\ne0[/tex]
