7.
[tex]Obw = 2\cdot3\sqrt{2}+2\cdot2\sqrt{3} = 6\sqrt{2}+4\sqrt{3} \neq 5\sqrt{5} \ - \ FALSZ\\\\P = 3\sqrt{2}\cdot2\sqrt{3} = 6\sqrt{2\cdot3} = 6\sqrt{6} \ - \ PRAWDA[/tex]
8.
[tex]I. \ \ \sqrt[3]{216} = 6 = \sqrt{6^{2}} = \sqrt{36}\\\\II. \ \ 3\sqrt{3} = \sqrt{3^{2}\cdot3} = \sqrt{3^{3}} = \sqrt{27}\\\\III. \ \ 2\sqrt{10} = \sqrt{2^{2}\cdot10} = \sqrt{4\cdot10} = \sqrt{40}\\\\\sqrt{27} < \sqrt{36} <\sqrt{40}\\\\Odp. \ A. \ II. \ I. \ III.[/tex]
