Odpowiedź :
[tex]6=(2a-5)\cdot (-2)+2b+1\\1=(2a-5)\cdot 5+2b+1\\\\6=-4a+10+2b+1\\1=10a-25+2b+1\\\\-4a+2b=-5\\10a+2b=25\\\\4a-2b=5\\\underline{10a+2b=25}\\14a=30\\\\a=\dfrac{30}{14}=\dfrac{15}{7}\\\\\\4\cdot\dfrac{15}{7}-2b=5\\\2b=\dfrac{60}{7}-\dfrac{35}{7}\\\2b=\dfrac{25}{7}\\\\b=\dfrac{25}{14}[/tex]