Odpowiedź:
[tex] {x}^{2} - 2x - x + 2 = 0[/tex]
[tex] {x}^{2} - 3x + 2 = 0[/tex]
liczymy deltę
[tex]delta = {( - 3)}^{2} - 4 \times 1 \times 2 = 9 - 8 = 1 \: \: \: \: \: \sqrt{1} = 1[/tex]
[tex]x1 = \frac{3 - 1}{2} = 1[/tex]
[tex]x2 = \frac{3 + 1}{2} = 2[/tex]
