Zad 1
C.
Zad 2
x + x + 9 = 77 | -9
2x = 68 | :2
x = 34
Zad 3
a) 3x + 10 = 37 | -10
3x = 27 | :3
x = 9
[tex]b)\frac{2x-3}{4} = \frac{x + 5}{3} | *12\\3(2x-3) = 4(x+5)\\6x - 9 = 4x + 20 | +9 -4x\\2x = 29 | :2\\x = \frac{29}{2} \\x =14 \frac{1}{2}[/tex]
c) 2x² + 6x = (x + 5)(2x - 1)
2x² + 6x = 2x² - x + 10x - 5 | -2x²
6x = 9x - 5 | +5 -6x
5 = 3x | :3
[tex]\frac{5}{3}=x \\1\frac{2}{3} =x[/tex]
Mam nadzieję że pomogłam i liczę na naj. ♥
