Odpowiedź:
3) [tex]x^2 + 3^2 = (2\sqrt{3})^2[/tex]
[tex]x^2 + 9 = 12[/tex]
[tex]x^2 = 12 - 9[/tex]
[tex]x=\sqrt{3}[/tex]
4) tu można obliczyć ze wzoru na przekatna kwadratu: [tex]9\sqrt{2}[/tex]
[tex]9^2+9^2=d^2[/tex]
[tex]d^2 = 81 + 81[/tex]
[tex]d^2 = 162[/tex]
[tex]d=9\sqrt{2}[/tex]
[tex]3^{2} + x^{2} = (2\sqrt{3} )^{2} \\x^{2} = 12 - 9\\x^{2} = 3\\x = \sqrt{3}[/tex]
[tex]9^{2} + 9^{2} = d^{2} \\81 + 81 = d^{2}\\162 = d^{2}\\\sqrt{162} = d\\9\sqrt{2} = d[/tex]
:)
