[tex]4x^{2}-x-3 > 0\\\\M. \ zerowe:\\\\\Delta = b^{2}-4ac = (-1)^{2}-4\cdot4\cdot(-3)=1+48 = 49\\\\\sqrt{\Delta} = \sqrt{49} = 7\\\\x_1 =\frac{1-7}{2\cdot4} = \frac{-6}{8} = -\frac{3}{4}\\\\x_2 = \frac{1+7}{8} = \frac{8}{8} = 1\\\\a = 4 > 0, \ to \ ramiona \ paraboli \ skierowane \ do \ gory\\\\x \in (-\infty; -\frac{3}{4}) \ \cup \ (1;+\infty)[/tex]
