[tex]a) \ (\frac{1}{4})^{2}\times 4^{3} = 4^{-2}\times4^{3} = 4^{-2+3} = 4^{1} = 4\\\\b) \ 6\times(\frac{1}{3})^{2}-12\times(-\frac{1}{2})^{2} = 6\times\frac{1}{9}-12\times\frac{1}{4} = \frac{2}{3}-3 = -2\frac{1}{3}\\\\c) \ -4^{2}-(-3)^{2}:(\frac{1}{3})^{2} = -16-9:\frac{1}{9} = -16-9\times9 = -16-81 = -97[/tex]
