Rozwiązane

potrzebne utro
proszę pomocy

[tex]a. \: \: {( \frac{1}{4}) }^{2} \times {4}^{3} = [/tex]
[tex]b. \: \: \: 6 \times {( \frac{1}{3} )}^{2} - 12 \times {( - \frac{1}{2} )}^{2} = [/tex]
[tex]c. \: \: \: \: - {4}^{2} - {( - 3)}^{2} \div {( \frac{1}{3}) }^{2} = [/tex]


​



Odpowiedź :

Basetla

[tex]a) \ (\frac{1}{4})^{2}\times 4^{3} = 4^{-2}\times4^{3} = 4^{-2+3} = 4^{1} = 4\\\\b) \ 6\times(\frac{1}{3})^{2}-12\times(-\frac{1}{2})^{2} = 6\times\frac{1}{9}-12\times\frac{1}{4} = \frac{2}{3}-3 = -2\frac{1}{3}\\\\c) \ -4^{2}-(-3)^{2}:(\frac{1}{3})^{2} = -16-9:\frac{1}{9} = -16-9\times9 = -16-81 = -97[/tex]

Inne Pytanie