I.
a)
[tex]4^{2} +4^{2}=x^{2} \\16+16=x^{2} \\32=x^{2} \\\sqrt{32}=x\\4\sqrt{2}cm=x[/tex]
b)
[tex]y^{2} +y^{2} =5^{2} \\2y^{2} =25\\y^{2} =12,5\\y=\sqrt{12,5} cm[/tex]
II.
a)
[tex]a^{2} +a^{2} =2a^{2} \\\sqrt{2a^{2} } =a\sqrt{2}[/tex]
boki tego trójkąta to [tex]a, a, a\sqrt{2}[/tex]
b)
[tex]x^{2} +x^{2} =a^{2} \\2x^{2} =a^{2} \\x^{2} =\frac{1}{2}a^{2} \\x=a\sqrt{\frac{1}{2} }[/tex]
boki tego trójkąta mają [tex]a, a\sqrt{\frac{1}{2} } ,a\sqrt{\frac{1}{2} }[/tex]
