Odpowiedź:
[tex]\begin{cases}\frac{2x-y}{3}=\frac{3x+y}{2}\\x=2(x+y+1)\end{cases}\\\\\\\begin{cases}2(2x-y)=3(3x+y)\\x=2x+2y+2\end{cases}\\\\\\\begin{cases}4x-2y=9x+3y\\x-2x-2y=2\end{cases}\\\\\\\begin{cases}4x-2y-9x-3y=0\\-x-2y=2\end{cases}\\\\\\\begin{cases}-5x-5y=0\ \ /:(-5)\\-x-2y=2\end{cases}\\\\\\+\begin{cases}x+y=0\\-x-2y=2\end{cases}\\---------\\-y=2\ \ /\cdot(-1)\\y=-2\\\\\\x+(-2)=0\\\\x-2=0\\\\x=2\\\\\\\begin{cases}x=2\\y=-2\end{cases}[/tex]
