oblicz: √121, √333^2, √20x√5, √20-√5
dam naj

√121 = 11
√333² = 333
√20 * √5 = √(20 * 5) = √100 = 10
√20 - √5 = √(4 * 5) - √5 = 2√5 - √5 = √5
[tex]\sqrt{121} = \sqrt{11^{2}} = 11\\\\\sqrt{333^{2}} = 333\\\\\sqrt{20}\cdot\sqrt{5} = \sqrt{20\cdot5} = \sqrt{100} = \sqrt{10^{2}} = 10\\\\\sqrt{20}-\sqrt{5} = \sqrt{4\cdot5}-\sqrt{5} = \sqrt{4}\cdot\sqrt{5}-\sqrt{5} = 2\sqrt{5}-\sqrt{5} = \sqrt{5}[/tex]