Odpowiedź:
[tex](x-4)(x+5)-x^2=3\\\\x^2+5x-4x-20-x^2=3\\\\x-20=3\\\\x=3+20\\\\x=23\\\\\\x^2-2=(x+2)(x+4)\\\\x^2-2=x^2+4x+2x+8\\\\x^2-2=x^2+6x+8\\\\x^2-x^2-6x=8+2\\\\-6x=10\ \ /:(-6)\\\\x=-\frac{10}{6}\\\\x=-\frac{5}{3}\\\\x=-1\frac{2}{3}[/tex]
