Odpowiedź :
[tex]1)\\\\\begin{cases}5x-3y= -11\ \ |*4\\2x+4y=6 \ \ |*3\end{cases}\\\\\begin{cases}20x-12y= -44\\6x+12y=18 \end{cases}\\+---------\\26x=-26\ \ |:26\\\\x=-1\\\\5x-3y=-11\\\\5*(-1)-3y=-11\\-5-3y=-11 \\-3y=-11+5\\-3y=-6\ \ |:(-3)\\y=2\\\\\begin{cases}x=-1\\y=2 \end{cases}[/tex]
[tex]2)\\\\\begin{cases} \frac{1}{4}x+3y=2,5\ \ |*4\\ \frac{1}{2}x-2y=3\ \ |*(-2)\end{cases} \\\\\begin{cases} x+12y=10\\ -x+4y=-6 \end{cases} \\+---------\\16y=4\ \ |:16\\y=\frac{4}{16}=\frac{1}{4}\\\\\\ \frac{1}{2}x-2y=3\\\frac{1}{2} x-2 *\frac{1}{4}=3\\\frac{1}{2}x- \frac{1}{2}=3\\\\\frac{1}{2}x= \frac{6}{2}+\frac{1}{2}\\\\\frac{1}{2}x=\frac{7}{2}\ \ |*2\\x=7\\\\\begin{cases}x=7\\y=\frac{1}{4} \end{cases}[/tex]