Odpowiedź:
P = 378 [j²]
Obw = 90 [j]
Szczegółowe wyjaśnienie:
[tex]b = 25\\c = 29\\h = 20\\a = ?\\P = ?\\Obw = ?\\\\a_1^{2} + 20^{2} = 25^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a_2^{2}+20^{2} = 29^{2}\\\\a_1^{2} = 400 = 625 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a_2^{2}+400=841\\\\a_1^{2} = 625-400 = 225 \ \ \ \ \ \ \ \ a_2^{2} =841-400=441\\\\a_1 = \sqrt{225} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a_2 =\sqrt{441}\\\\a_1 = 15 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a_2 = 21[/tex]
[tex]a = a_1 + a_2 = 15+21 = 36\\\\\\P=\frac{1}{2}ah = \frac{1}{2}\cdot36\cdot21 = 18\cdot21 = 378 \ [j^{2}]\\\\Obw = a+b+c = 36+25+29 = 90 \ [j][/tex]
