[tex]dane:\\F = 4 \ N\\v = 5\frac{m}{s}\\t = 0,3 \ min = 0,3\cdot60 \ s = 18 \ s\\szukane:\\m = ?\\\\Rozwiazanie\\\\a = \frac{v}{t} = \frac{5\frac{m}{s}}{18 \ s} =\frac{5}{18}\frac{m}{s^{2}}=\frac{5}{18}\frac{N}{kg}\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\m = \frac{4 \ N}{\frac{5}{18}\frac{N}{kg}} = 4\cdot\frac{18}{5} \ kg\\\\m = 14,4 \ kg[/tex]
