Rozwiązane

Zapisz w postaci jednej potęgi i oblicz,

[tex]9^7:9^4=\\2^2*2^4=\\((\frac{1}{3})^2)^3[/tex].



Odpowiedź :

[tex] {9}^{7} \div {9}^{4} = {9}^{7 - 4} = {9}^{3} = 729[/tex]

[tex] {2}^{2} \times {2}^{4} = {2}^{2 + 4} = {2}^{6} = 64[/tex]

[tex]( {( \frac{1}{3} )}^{2} ) ^{3} = {( \frac{1}{3}) }^{2 \times 3} = {( \frac{1}{3}) }^{6} = \frac{1}{729} [/tex]

Odpowiedź:

[tex] {9}^{7} \div {9}^{4} = {9}^{3} = 9 \times 9 \times 9 = 729[/tex]

[tex] \ {2}^{2} \times {2}^{4} = {2}^{6} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 64[/tex]

[tex](( \frac{1}{3} ) {}^{2} ) {}^{3} = (\frac{1}{3} ) {}^{6} = \frac{1}{729} [/tex]

Pozdrawiam.