1. Masa cząsteczkowa heksanu= 6*12+14*1=72+14=86u %C=(6*12)/86*100%=83,72% %H=(1*14)/86*100%=16,28%
2.
1)C5H12+8O2−−>5CO2+6H2OC5H12+8O2−−>5CO2+6H2O-spalanie całkowite
2)C5H12+112O2−−>5CO+6H2OC5H12+112O2−−>5CO+6H2O-półspalanie
3)C5H12+3O2−−>5C+6H2OC5H12+3O2−−>5C+6H2O-spalanie niecałkowite
3. 12n + 1(2n-2) = 54u 12n + 2n - 2 = 54 14n = 54 + 2 14n = 56 n = 56/14 n = 4 C4H6 -- butin lub butyn
4. a)bromu do butenu
CH3-CH=CH-CH3 + Br2---->CH3-CH(Br)-CH(Br)-CH3..2,3-dibromobutan
b)chloru do propynu
CH≡C-CH3 + 2Cl2---->CH(Cl)2-C(Cl)2-CH3.....1,1,2,2-tetrachloropropan
c)wodoru do pentynu
CH≡C-CH2-CH2-CH3 + 2H2---->CH3-CH2-CH2-CH2-CH3.....pentan
