Odpowiedź:
K = (- 2 , 1 ) , L = ( 4 , 3 ) , M = (0 , 5 )
xk = - 2 , xl = 4 , xm = 0 , yk = 1 , yl = 3 , ym = 5
Oznaczam środki boków trójkąta punktami N , O , P
N = (xn , yn)
xn = (xk + xl)/2 = (- 2 + 4)/2 = 2/2 = 1
yn = (yk + yl)/2 = (1 + 3)/2 = 4/2 = 2
N = ( 1 , 2 )
O = (xo , yo)
xo = (xm + xl)/2 = (0 + 4)/2 = 4/2 = 2
yo = (ym + yl)/2 = (5 + 3)/2 = 8/2 = 4
O = ( 2 , 4 )
P = (xp , yp)
xp = (xk + xm)/2 = (- 2 + 0)/2 = - 2/2 = - 1
yp = (yk + ym)/2 = (1 + 5)/2 = 6/2 = 3
P = ( - 1 , 3 )
Rysunek w załączniku
