Odpowiedź :
m H2SO4 = 2*1u+1*32u+4*16u = 98u
%H = (2u/98u)*100%=2,04%
%S = (32u/98u)*100% = 32,65%
%O = (64u/98u)*100% = 65,31%
Odp.: III
m H2SO4 = 2*1u+1*32u+4*16u = 98u
%H = (2u/98u)*100%=2,04%
%S = (32u/98u)*100% = 32,65%
%O = (64u/98u)*100% = 65,31%
Odp.: III