i 3•(x+2)=2(x+5)
j 6•(x+1)= -4 (x+3)
k -2(x-1)=8•x+2
daje naj ​



Odpowiedź :

[tex]i) \: 3(x + 2) = 2(x + 5) \\ 3x + 6 = 2x + 10 \\ 3x - 2x = 10 -6 \\ x = 4[/tex]

[tex]j) \: 6(x + 1) = - 4(x + 3) \\ 6x + 6 = 4x - 12 \\ 6x - 4x = - 12 - 6 \\ 2x = - 18 \: \: | \div 2 \\ x = - 9[/tex]

[tex]k) \: - 2(x - 1) = 8 \times x + 2 \\ - 2x + 2 = 8x + 2 \\ - 2x - 8x = 2 - 2 \\ - 10x = 0 \: \: | \div ( - 10) \\ x = 0[/tex]