Odpowiedź:
[tex]\left \{ {{\frac{4x-y}{3}-\frac{x+2y}{2} =\frac{8}{3}/*6 } \atop {\frac{x+y}{2}+\frac{4x-9y}{2} =8/*2}} \right.[/tex]
[tex]\left \{ {{8x-2y-3x-6y=16} \atop {x+y+4x-9y=16}} \right.[/tex]
[tex]\left \{ {{5x-8y=16/*(-1)} \atop {5x-8y=16}} \right.[/tex]
[tex]\left \{ {{-5x+8y=-16} \atop {5x-8y=16}} \right.[/tex]
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0=0
x∈R
Szczegółowe wyjaśnienie:
