Odpowiedź :
Odpowiedź:
Szczegółowe wyjaśnienie:
Zad 1
q = 8 / (-6) = -4/3
a₁ = -6 / q = -6 * (-3/4) = 9/2
a₄ = a₃ * q = 8 * (-4/3) = -32/3
a₈ = a₁ * q⁷ = 9/2 * (-4/3)⁷ = -8192/243
Zad 2
a₁ = -2, q = -2
S₆ = -2 * (1 - (-2)⁶) / (1 - (-2))
S₆ = 42
Zad 3
a₁ = -15, a₂ = 30 ⇒ q = -2
S₈ = -15 * (1 - (-2)⁸) / (1 - (-2))
S₈ = 1275
Zad 4
a₆ = 4, a₁₀ = 1/64
a₁₀ / a₆ = (a₁ * q⁹) / (a₁ * q⁵) = q⁴
1/64 * 1/4 = q⁴
4⁻⁴ = q⁴
q = ±4⁻¹ = ±1/4
a₁ = a₆ / q⁵ = 4 * (±1/4)⁵ = ±1/256
Odp: aₙ = -1/256 * (-1/4)ⁿ⁻¹ ∨ aₙ = 1/256 * (1/4)ⁿ⁻¹.
1.
a₃= a₂*q
8= -6 *q
q= -8/6
q= -4/3
a₂=a₁*q
-6= a₁ * (-4/3)
a₁= 4,5
a₄= 4,5 * q³
a₄ = - 32/3
a₅= (-32/3) * (-4/3) = 128/9
a₈= (128/9) * (-4/3)³ = - 8192/243
2. ( ciąg -2,-4, 8 nie jest ciągiem geometrycznym ale domyślam się że tam miała być -8)
S₆=? q=2
n= 6
S₆= -2* [tex]\frac{1-q^{6} }{1-q }[/tex]
S₆= -126
3.
S₈=?
q= -2
[tex]S_{8} = -15 \frac{1-q^{8} }{1-q}[/tex]
S₈= 1275
4.
a₁₀= a₆*q⁴
1/64 = 4 * q⁴
q= 1/4 v q = -1/4
a₆= a₁ * q⁵
I. q = 1/4 II. q= -1/4
a₁=4096 a₁=-4096
Wzór ogólny: [tex]a_{n} = a_{1} * q^{n-1}[/tex]
I. q = 1/4
aₙ= 4096 * (1/4)ⁿ : (1/4)
aₙ= 16384* 1/4ⁿ
aₙ= (4^7)/(4ⁿ)
aₙ=4⁽⁷⁻ⁿ⁾
II. q = -1/4
aₙ= 4096 * (-1/4)ⁿ : (-1/4)
aₙ= - 16 384 * (-1/4)ⁿ
aₙ= [tex]\frac{(-1)^{n} (-4)^{7} }{4^{n} }[/tex]