Odpowiedź :
1.
[tex]0=10x+17[/tex]
[tex]x0 = \frac{-17}{10}[/tex]
2.
[tex]sin^{2} \beta +cos^{2}\beta = 1[/tex]
[tex]cos^{2}\beta = \frac{3}{4}[/tex]
[tex]cos\beta = \frac{\sqrt{3} }{2}[/tex]
3.
Δ[tex]=b^2 - 4ac[/tex] =[tex]49[/tex]
pierwiastek z delty = 7
x1 = 1
x2 = [tex]\frac{-10}{4}[/tex]