Odpowiedź:
Z twierdzenia Pitagorasa:
a. [tex]2^{2} +5^{2} = x^{2}[/tex]
[tex]4 + 5 = x^{2}[/tex]
[tex]x^{2} = 9[/tex]
[tex]x = \sqrt{9}[/tex]
[tex]x = 3[/tex]
b. [tex]2^{2} = x^{2} + 1^{2}[/tex]
[tex]4 = x^{2} + 1[/tex]
[tex]x^{2} = 4 - 1[/tex]
[tex]x^{2} = 3\\x = \sqrt{3}[/tex]
c.
[tex]5^{2} = x^{2} + 2^{2} \\25 = x^{2} + 4\\x^{2} = 21\\x = \sqrt{21}[/tex]
d.
[tex]x^{2} = 7^{2} + 3^{2} \\x^{2} = 49 + 9\\x^{2} = 58\\x = \sqrt{58} \\[/tex]
Mam nadzieję, że pomogłam :>
