Odpowiedź:
[tex]-3x(2-4x)=6x(2x-3)\\\\-6x+12x^2=12x^2-18x\\\\-6x+12x^2-12x^2+18x=0\\\\12x=0\ \ /:12\\\\x=0\\\\\\\\3-2x(3-x)=2x^2-3(x+2)\\\\3-6x+2x^2=2x^2-3x-6\\\\-6x+2x^2-2x^2+3x=-6-3\\\\-3x=-9\ \ /:(-3)\\\\x=3[/tex]
[tex](2x-1)(2-3x)=(2-3x)(2x+3)\\\\4x-6x^2-2+3x=4x+6-6x^2-9x\\\\7x-6x^2-2=-5x+6-6x^2\\\\7x-6x^2+5x+6x^2=6+2\\\\12x=8\ \ /:12\\\\x=\frac{8}{12}\\\\x=\frac{2}{3}\\\\\\\\(4x-3)(3x-2)-(6x+4)(2x-3)=4\\\\12x^2-8x-9x+6-(12x^2-18x+8x-12)=4\\\\12x^2-17x+6-12x^2+18x-8x+12=4\\\\-7x+18=4\\\\-7x=4-18\\\\-7x=-14\ \ /:(-7)\\\\x=2[/tex]
