Odpowiedź:
[tex]a)\ \ \sqrt{49}-\sqrt[3]{-64}=7-(-4)=7+4=11\\\\b)\ \ 4\sqrt{\frac{1}{25}}+\frac{\sqrt{36}}{2}=4\cdot\frac{1}{5}+\frac{6}{2}=\frac{4}{5}+3=3\frac{4}{5}\\\\c)\ \ \sqrt[3]{81\cdot\sqrt{81}}=\sqrt[3]{81\cdot9}=\sqrt[3]{9^2\cdot9}=\sqrt[3]{9^3}=9\\\\d)\ \ \sqrt{4\sqrt{4\sqrt{16}}}=\sqrt{4\sqrt{4\cdot4}}=\sqrt{4\sqrt{16}}=\sqrt{4\cdot4}=\sqrt{16}=4\\\\e)\ \ \sqrt{25}-\sqrt{16}+\sqrt{25-16}=5-4+\sqrt{9}=1+3=4\\\\f)\ \ \sqrt{900}:\sqrt[3]{125}+\sqrt{36}=30:5+6=6+6=12[/tex]
