Odpowiedź:
[tex](\frac{1}{16})^{6}=(\frac{1}{4^{2}})^{6}=(\frac{1}{4})^{12}[/tex]
[tex]27^{12}=(3^{3})^{12}=3^{36}[/tex]
[tex]6^{22}=(6^{2})^{11}=36^{11}[/tex]
[tex]25^{30}=(5^{2})^{30}=5^{12})^{5}[/tex]
[tex]64^{28}=(8^{2})^{28}=8^{14})^{4}[/tex]
[tex](\frac{1}{49})^{13}=(\frac{1}{7^{2}})^{13}=(\frac{1}{7})^{26}[/tex]
Szczegółowe wyjaśnienie:
[tex]a^{n})^{m}=a^{n*m}[/tex]