Odpowiedź:
zadanie 1
[tex](2ab^{2} ) {}^{3} = {2}^{3} \times {a}^{3} \times {b}^{6} [/tex]
[tex]( \frac{a}{7}) {}^{2} = \frac{ {a}^{2} }{49} [/tex]
zadanie 2
a) n=18, m=6
b) n=15, m=39 (n przy 13, m przy 6)
zadanie 3
[tex] {0.2}^{3} \times {10}^{3} = {2}^{3} = 2 \times 2 \times 2 = 8[/tex]
[tex]( \frac{3}{5} )^{4} \div ( { \frac{1}{5}) }^{4} = ( \frac{3}{5} ) {}^{4} \times ( \frac{5}{1} ) {}^{4} = {3}^{4} = 81[/tex]
