Odpowiedź:
[tex]a = 9 \times {9}^{6} = {9}^{7} = ({3}^{2} ) ^{7} = {3}^{14} \\ b = {27}^{5} = ( {3}^{3} )^{5} = {3}^{15} \\ c = {81}^{3} = ( {3}^{4} ) ^{3} = {3}^{12} \\ a \times b = {3}^{14} \times {3}^{15} = {3}^{29} \\ \frac{b}{c} = \frac{ {3}^{15} }{ {3}^{12} } = {3}^{3} \\ a \times b \times c = {3}^{14} \times {3}^{15} \times {3}^{12} = \\ = {3}^{14 + 15 + 16} = {3}^{45} [/tex]
