Odpowiedź:
a)
[tex]Pc = 2Pp + Pb \\Pp = 3 cm * 3 cm = 9cm^2\\Pb = 4 * 3cm * 9 cm = 108 cm^2 \\Pc = 2 * 9cm^2 + 108 cm^2 = 126 cm^2\\\\V = Pp * H\\H = 9 cm \\Pp = 9 cm^2 \\V = 9cm^2 * 9cm = 81 cm^3[/tex]
b)
[tex]Pc = 2Pp + Pb \\Pp = \frac{5^2\sqrt{3} }{4} = \frac{25\sqrt{3} }{4} = 6,25\sqrt{3} (dm^2)\\Pb = 3 * 5 dm * 8 dm = 120 dm^2\\Pc = 6,25\sqrt{3} dm^2 + 120 dm^2 = (120 + 6,25\sqrt{3} ) dm^2\\\\V = Pp * H \\H = 8 dm \\Pp = 6,25\sqrt{3} dm^2\\V = 6,25\sqrt{3} dm^2 * 8 dm = 50\sqrt{3} dm^3[/tex]
c)
[tex]Pc = Pp + Pb \\Pp = 6 * \frac{4^2 \sqrt{3} }{4} = 6 * \frac{16\sqrt{3} }{4} = 6 * 4\sqrt{3} = 24\sqrt{3} (cm^2)\\Pb = 6 * 4 cm * 7 cm = 168 cm^2\\Pc = 24\sqrt{3} cm^2 + 168 cm^2 = (168 + 24\sqrt{3} )cm^2\\\\V = Pp * H\\H = 7 cm\\Pp = 24\sqrt{3} cm^2\\V = 24\sqrt{3} cm^2 * 7 cm = 168\sqrt{3} cm^3[/tex]
