Odpowiedź :
a= ?
b=12
c=13
Tw. Pitagorasa : a^2 + b^2 = c^2
a^2 + 12^2 = 13^2
a^2 + 144 = 169
a^2 = 169 - 144
a^2 = 25
a = 5
[tex]a^{2} + 12^{2} = 13^{2} \\a^{2} + 144 = 169 | -144\\a^{2} = 25\\a = 5\\----------------\\\sqrt{6} ^{2} + \sqrt{3} ^{2} = b^{2} \\ 6 + 3 = b^{2} \\9 = b^{2}\\b = 3[/tex]
Jakby co, to pierwiastek do kwadratu po prostu usuwa pierwiastek.