Odpowiedź:
zadanie 5
a)
[tex]( - \frac{2}{7} ) ^{2} = \frac{4}{49} [/tex]
[tex]( - \frac{3}{10} )^{3} = - \frac{27}{100} [/tex]
b)
[tex]( - 0.2) ^{3} = - 0.008[/tex]
[tex]( - 0.15) ^{2} = 0.0225[/tex]
c)
[tex]( - 3 \frac{1}{3} ) ^{3} = ( - { \frac{10}{3}) }^{3} = - \frac{100}{27} = - 3 \frac{19}{27} [/tex]
[tex]( { - 2.5)}^{2} = 6.25[/tex]
zadanie 6
a)
[tex] - {1.5}^{2} = - 2.25[/tex]
b)
[tex] - \frac{1}{ {2}^{3} } = - \frac{1}{8} [/tex]
c)
[tex] - (1 \frac{1}{4} ) ^{2} = - ( { \frac{5}{4} )}^{2} = - \frac{25}{16} = - 1 \frac{9}{16} [/tex]
d)
[tex] - \frac{ {2}^{2} }{5} = - \frac{4}{5} [/tex]
e)
[tex] { - 1}^{2} = - 1[/tex]
zadanie 7
a)
[tex]2 \times {3}^{3} - 3 - {2}^{2} = 2 \times 27 - 3 \times 4 = 54 - 12 = 42[/tex]
[tex]5 \times {2}^{3} - 4 \times {3}^{2} = 5 \times 8 - 4 \times 9 = 40 - 36 = 4[/tex]
b)
[tex]( - \frac{3}{4} )^{2} + ( - { \frac{1}{2} )}^{3} = \frac{9}{16 } + ( - \frac{1}{8} ) = \frac{9}{16} - \frac{2}{16} = \frac{7}{16} [/tex]
[tex]( - \frac{2}{3} )^{3} - ( - 5) ^{3} = - \frac{8}{27} + 125 = 124 \frac{19}{27} [/tex]
c)
[tex] { - 2}^{3} \times 3 + ( - \frac{1}{2} ) ^{2} = - 8 \times 3 + \frac{1}{4} = - 24 + \frac{1}{4} = - 23 \frac{3}{4} [/tex]
[tex]( - 2 \frac{1}{2} ) {}^{2} + (3 \frac{1}{2} ) {}^{2} = ( - \frac{5}{2} ) {}^{2} + ( { \frac{7}{2} )}^{2} = \frac{25}{4} + \frac{49}{4} = \frac{74}{4} = 18 \frac{1}{2} [/tex]
zadanie 8
[tex] - 2.4 \times (3.75 - 4 \frac{2}{3} ) + ( \frac{2}{5} ) {}^{2} = - 2 \frac{2}{5} \times (3 \frac{9}{12} - 4 \frac{8}{12} ) + \frac{4}{25} = - \frac{12}{5} \times ( - \frac{11}{12} ) + \frac{4}{25} = \frac{11}{5} + \frac{4}{25} = 2 \frac{5}{25} + \frac{4}{25} = 2 \frac{9}{25} [/tex]
odpowiedź B
zadanie 9
[tex]5.5 = 5 \frac{2}{4} \\ 5 \frac{2}{4} - 3 \frac{1}{4} = 2 \frac{1}{4} = \frac{9}{4} \\ 5 \frac{2}{4} + 3 \frac{1}{4} = 8 \frac{3}{4} = \frac{35}{4} \\ pk = {5.5}^{2} = 30.25 \\ pp = \frac{9}{4} \times \frac{35}{4} = \frac{315}{16} = 19 \frac{11}{16} [/tex]
pk to pole kwadratu,a pp pole prostokąta
Teraz liczę o ile jest większe pk od pp
[tex]30.25 - 19 \frac{11}{16} = 30 \frac{1}{4} - 19 \frac{11}{16} = 30 \frac{4}{16} - 19 \frac{11}{16} = 29 \frac{20}{16} - 19 \frac{11}{16} = 10 \frac{9}{16} [/tex]
