Odpowiedź:
Pc = 2·Pp + Pb = 2 · [tex]6 cm^{2}[/tex] + [tex]84 cm^{2}[/tex] = [tex]12cm^{2} + 84 cm^{2} = 96 cm^{2}[/tex]
Pp = [tex]\frac{ab}{2} = \frac{3*4}{2} = \frac{12}{2} = 6 cm[/tex]²
Pb = 4·7 + 5·7 + 3·7 = 28 + 35 + 21 = [tex]84 cm^{2}[/tex]
Odp. Pole powierzchni wynosi [tex]96 cm^{2}[/tex].
