Erykopal90
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pomoze ktos? dam naj ale za cale zadanie



Pomoze Ktos Dam Naj Ale Za Cale Zadanie class=

Odpowiedź :

Agataa112233

Odpowiedź:

[tex] {2}^{5} \div ( {2}^{3} \times {2}^{0} ) = {2}^{5} \div {2}^{3} = {2}^{2} = 4[/tex]

[tex] {( {2}^{8} \div {2}^{7}) }^{3} = { {(2}^{1} )}^{3} = {2}^{3} = 8[/tex]

[tex] \frac{ { {(2}^{6} )}^{3} }{ {2}^{15} } = \frac{ {2}^{18} }{ {2}^{15} } = {2}^{3} = 8[/tex]

[tex] {( {2}^{7}) }^{3} \div { {(2}^{4}) }^{5} = {2}^{21} \div {2}^{20} = {2}^{1} = 2[/tex]

[tex] { {(2}^{4}) }^{6} \div {(2}^{13} \times {2}^{7} ) = {2}^{24} \div {2}^{20} = {2}^{4} = 16[/tex]

[tex] {(2}^{11} \div {2}^{3} ) \div { {(2}^{4} )}^{2} = {2}^{8} \div {2}^{8} = {2}^{0} = 1[/tex]

[tex] { {(2}^{3} \times {2}^{2} ) }^{3} \div {2}^{12} = { {(2}^{5}) }^{3} \div {2}^{12} = {2}^{15} \div {2}^{12} = {2}^{3} = 8[/tex]

[tex] { {(2}^{5} \div {2}^{3}) }^{6} \div {2}^{10} = {( {2}^{2} )}^{6} \div {2}^{10} = {2}^{12} \div {2}^{10} = {2}^{2} = 4[/tex]

Zonkilfn

a) [tex]2^{5} : 2^{3} = 2^{5-3} = 2^{2}[/tex]

b) [tex](2^{1})^{3} = 2^{3}[/tex]

c) [tex]\frac{2^{18} }{2^{15} } = 2^{3}[/tex]

d) [tex]2^{21} : 2^{20} = 2^{1} = 2[/tex]

e)[tex]2^{24} : (2^{20} ) = 2^{4}[/tex]

f) [tex]2^{8} : 2^{8} = 2[/tex]

g) [tex](2^{5} )^{3} : 2^{12} = 2^{15} : 2^{10} = 2^{15-10} = 2^{5}[/tex]

h) [tex](2^{2} )^{6} : 2^{10} = 2^{12} :2^{10} = 2^{12-10} = 2^{2}[/tex]

liczę na naj, troszkę się napracowałem i mam nadzieję, że pomogłem :)

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