[tex]Zadanie\\\\a)\\\\T=6(v-x)\ \ \mid:6\\\\\frac{T}{6} =v-x\ \ \mid-v\\\\\frac{T}{6}-v=-x\ \ \mid\cdot(-1)\\\\v-\frac{T}{6} =x\\\\x=v-\frac{T}{6} \ \ \ \ lub\ \ \ \ x=\frac{6v-T}{6}\\\\\\b) \\\\V-a=3(a-bx)\\\\V-a=3a-3bx\ \ \mid-3a\\\\V-4a=-3bx\ \ \mid:(-3b)\\\\ \frac{V-4a}{-3b}=x\\\\\frac{4a-V}{3b}=x\\\\x=\frac{4a-V}{3b}\\\\Zal.\ b\ne0[/tex]
