Odpowiedź:
[tex]4^{x-1} = 8^{32}[/tex]
[tex]2^{2(x-1)} = 2^{3*32}[/tex]
2(x-1) = 3*32
2x-2 = 96
2x = 96+2
2x = 98 /2
x = 49
[tex]2^{x-1} < 64[/tex]
[tex]2^{x-1} < 2^{6}[/tex]
x-1 <6
x <6+1
x<7
[tex](\frac{2}{5})^{x} > \frac{8}{125}[/tex]
[tex](\frac{2}{5})^{x} > (\frac{2}{5})^{3}[/tex]
x=3
Szczegółowe wyjaśnienie:
