[tex]dane:\\f \ - \ ogniskowa\\x = 4f\\szukane:\\p = ?\\\\Rozwiazanie\\\\Z \ rownania \ soczewki\\\\\frac{1}{f} = \frac{1}{x}+\frac{1}{y}\\\\\frac{1}{y} = \frac{1}{f} - \frac{1}{x}\\\\\frac{1}{y} = \frac{1}{f} -\frac{1}{4f}\\\\\frac{1}{y} = \frac{4-1}{4f}\\\\\frac{1}{y} = \frac{3}{4f}\\\\y = \frac{4f}{3}[/tex]
[tex]Powiekszenie \ obrazu:\\\\p = \frac{y}{x}\\\\p = \frac{\frac{4f}{3}}{4f} = \frac{1}{3}[/tex]
Odp. Powiększenie obrazu p = 1/3.
