[tex]dane:\\v_1 = 30\frac{km}{h}\\E_{k_1} = 40 \ kJ\\v_2 = 60\frac{km}{h} = 2v_1\\szukane:\\E_{k_2} ?\\\\Rozwiazanie\\\\E_{k_1} = \frac{mv_1^{2}}{2}\\\\E_{k_2} = \frac{mv_2^{2}}{2} = \frac{m\cdot(2v_1)^{2}}{2} = 4\cdot\frac{mv_1^{2}}{2} =4E_{k_1}\\\\E_{k_2} = 4\cdot40 \ kJ = 160 \ kJ[/tex]
Odp. Energia kinetyczna samochodu wyniosłaby 160 kJ.
