[tex]\sqrt{\frac{1}{4}}-\frac{1}{2}(3-\sqrt{64}) = \frac{1}{2}-\frac{1}2}(3-8) = \frac{1}{2}-\frac{1}{2}\cdot(-5) = \frac{1}{2}+\frac{5}{2} = \frac{6}{2} = 3\\\\\frac{\sqrt{26^{2}}}{\sqrt{49}+\sqrt{36}}\cdot\sqrt{0,0001} = \frac{26}{7+6}\cdot0,01=\frac{26}{13}\cdot0,01 = 2\cdot0,01 = 0,02\\\\\sqrt{8-\frac{8}{9}}-\sqrt{(\frac{8}{9})^{2}} = \sqrt{\frac{72}{9}-\frac{8}{9}}-\frac{8}{9} = \sqrt{\frac{64}{9}}-\frac{8}{9} = \frac{8}{3}-\frac{8}{9} = \frac{24}{9}-\frac{8}{9} = \frac{16}{9} = 1\frac{7}{9}[/tex]
[tex]15 + 2(\sqrt{5})^{2}+\sqrt{0} = 15 + 2\cdot5 + 0 = 15+10 = 25\\\\\sqrt{2\frac{1}{4}}-\sqrt{\frac{1}{4}} = \sqrt{\frac{9}{4}}-\frac{1}{2} = \frac{3}{2}-\frac{1}{2} = \frac{2}{2} = 1\\\\\frac{16+\sqrt{16}}{16}\cdot\sqrt{16} = \frac{16+4}{16}\cdot4} = \frac{20}{16}\cdot 4 = \frac{20}{4} = 5[/tex]
