[tex]dane:\\V = 6 \ dm^{3} = 0,006 \ m^{3}\\V_{z} = \frac{2}{3}V =\frac{2}{3}\cdot0,006 \ m^{3} = 0,004 \ m^{3}\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\F_{w} = d\cdot g\cdot V_{z}\\\\F_{w} = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,004 \ m^{3}\\\\F_{w} = 40 \ N[/tex]
